I'm not sure if the Code will allow this, but I would want to run two lines out there, one for the welder, and one for everything else, so that you don't have the lights dimming up and down (as much) from the welder.

- Amy M (Fair, SD), 03/25/2017

assuming 240 volts, 3% VD would be 7.2 voltsVD = 2 x I x L x R / 1,000, using the R per 1,000 feet in Table 8, Chapter 9.Transposing: max R = 1,000 x 7.2 volts / 2 x I x LL = 169 feetI = 21 amps (or 25 amps with lights?)so max R would be 1.1 to .85 ohm which means a #8 copper conductor would be required. (.809 ohm per 1,000 feet)Neutral could be downsized for 240 volt load.If you are running 120 volts, then maximum VD would be 3.6 volts.and max R would = 1,000 x 3.6 / 2 x 25 x 169 = .42 ohm, which corresponds to a #4 copper conductor.If you run less, you risk low voltage to appliances. Problem??? maybe, maybe not.

- Juanita Austin (Chualar, CA), 03/25/2017

As usual,I left out info:(..The welder is 230 volt,3 prong outlet(I am pulling 2 hots,nuetraland ground....thks

- George Koval (Wanamassa, NJ), 03/25/2017